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| Abdullah M.A. |
Posted: March 24, 2012 07:00 am
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![]() Forum Addict ++ ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Spamminator Taskforce Posts: 4,252 Member No.: 10,604 Joined: August 16, 2007 |
Hi guys,
I just would like to ask you if anyone know how to calculate the capacitor value (capacitance,voltage) required to connect with voltage regulator in a robot draw 3A,6v ( 5v go out from voltage regulator 7805 to supply the control circuit, 6v go to +Vcc of servo motor), the used battery is a lead Acid (6v, 10A). The reason of connecting capacitor,I've got restarting in microcontroller when the robot want to start moving. any help will be really appreciated. Abdullah -------------------- "A scientist can discover a new star, but he cannot make one. He would have to ask an engineer to do that."
"For an optimist the glass is half full, for a pessimist it's half empty, and for an engineer is twice bigger than necessary." |
| Colt45 |
Posted: March 24, 2012 07:44 am
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![]() Forum Addict ++ ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Trusted Members Posts: 3,747 Member No.: 1,333 Joined: October 02, 2004 |
A 6V battery really isn't high enough voltage for a 7805, 7.5V or 8V is necessary to not have drop-out.
So you'll need a low dropout regulator (LM1117 for example, but there are many). -------------------- >]:::|-
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| Geek |
Posted: March 24, 2012 07:55 am
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![]() Moderator Group: Moderators Posts: 8,891 Member No.: 62 Joined: July 23, 2002 |
LT1084?
-------------------- -= Gregg =-
"Ratings are for transistors.....tubes have guidelines" (please do not PM me for advice. Non-forum business messages will be ignored) |
| MacFromOK |
Posted: March 24, 2012 08:49 am
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Forum Addict ++ ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Spamminator Taskforce Posts: 12,945 Member No.: 5,314 Joined: June 04, 2006 |
Or a resistor or couple of diodes for the control circuit... 6V to 5V isn't much of a drop.
-------------------- Mac *
"Basic research is what I'm doing when I don't know what I'm doing." [Wernher Von Braun] * is not responsible for errors, consequential damage, or... anything. |
| johansen |
Posted: March 24, 2012 11:31 am
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![]() Forum Addict ++ ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Trusted Members Posts: 2,766 Member No.: 10,912 Joined: September 06, 2007 |
3 amps isn't a lot for a 10 ah battery.
1000 uf placed near the linear regulator should be fine. you also should have at least 100 uf per amp of motor current, placed close to the motor controller. -------------------- THREE WORDS YOU DO NOT WANT TO HEAR: "GLOBAL BANK HOLIDAY"
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| CWB |
Posted: March 24, 2012 11:44 am
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![]() Forum Addict ++ ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Spamminator Taskforce Posts: 19,509 Member No.: 15,154 Joined: May 15, 2008 |
"The reason of connecting capacitor,I've got restarting in microcontroller when the
robot want to start moving." voltage sag/drop under load . the surge/start current drawn by the motors is dropping the supply (battery) voltage . the LM1117 has a dropout voltage of 1.10-1.30 volts differential depending on load (Vin-Vout) as shown here : http://www.ti.com/lit/ds/symlink/lm1117-n.pdf the LT1084 has a bit better differential performance but still runs very close to the edge : http://pdf1.alldatasheet.com/datasheet-pdf...NER/LT1084.html the LDO regulators are a bit fussier to work with than their regular brothers (so to say) . tim mentioned this in another thread a while back ... they want to whistle more so than the regular versions (ie : 7805) . i would go with a schottky diode (.15V-.45V Vfwd) or a regular silicon rectifier (about .7 Vfwd) ... this is a possible simple solution with readily available parts . a "stiffening" cap on the "downstream" side of the diode will provide the needed current when the 6 volt line sags under the momentary load of the motors . it will also prevent back-feed of the stiffening capacitor into the 6 volt buss/supply . you might try about 2000 uF to start with . the size needed will depend on how much load is on the controller side and the duration of the sag in the 6 volt line . -------------------- "Know how to solve every problem that has been solved"
R. Feynman '88 |
| Sch3mat1c |
Posted: March 25, 2012 11:29 pm
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![]() Forum Addict ++ Group: Moderators Posts: 18,140 Member No.: 73 Joined: July 24, 2002 |
How much current does the controller draw?
If it's fairly high, you may be interested in a wide range switching regulator. SEPIC would be excellent here. Tim -------------------- Answering questions is a tricky subject to practice. Not due to the difficulty of formulating or locating answers, but due to the human inability of asking the right questions; a skill that, were one to possess, would put them in the "answering" category.
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| Nothing40 |
Posted: March 26, 2012 01:05 am
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![]() Forum Addict ++ ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Spamminator Taskforce Posts: 3,294 Member No.: 181 Joined: October 05, 2002 |
I'd just toss a diode or two in series with the micro's Vcc line..stick a 'big' cap after that,and call it good. KISS.
-------------------- "we need an e-kick-in-the-nuts button" -Colt45
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| Abdullah M.A. |
Posted: March 26, 2012 01:35 pm
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![]() Forum Addict ++ ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Spamminator Taskforce Posts: 4,252 Member No.: 10,604 Joined: August 16, 2007 |
Hi guys,
I used in the beginning 1N4007 with 2200 uF cap., but it does not work. seems I needed a fast diode, so I changed with schottcky diode SB360, so it worked fine. Thank you CWB and all of you guys. @ Tim about 300mA. -------------------- "A scientist can discover a new star, but he cannot make one. He would have to ask an engineer to do that."
"For an optimist the glass is half full, for a pessimist it's half empty, and for an engineer is twice bigger than necessary." |
| johansen |
Posted: March 26, 2012 04:56 pm
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![]() Forum Addict ++ ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Trusted Members Posts: 2,766 Member No.: 10,912 Joined: September 06, 2007 |
heh, if the reason the 1n4007 didn't work was because it was slow... man that's some serious spikes you got there!
the schottky diodes would have only dropped .2 volts instead of 1.1, so that's probably the difference. -------------------- THREE WORDS YOU DO NOT WANT TO HEAR: "GLOBAL BANK HOLIDAY"
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| CWB |
Posted: March 27, 2012 12:23 am
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![]() Forum Addict ++ ![]() ![]() ![]() ![]() ![]() ![]() ![]() Group: Spamminator Taskforce Posts: 19,509 Member No.: 15,154 Joined: May 15, 2008 |
yep ... it is the Vfwd difference between the two types .
the uPC needs 5 volts and the supply (battery) is 6 volts ... not much difference to play with . (i took it that abdulla had already done the small cap bypassing/decoupling at the uPC) i'm glad the simple fix worked (at least this time) . -------------------- "Know how to solve every problem that has been solved"
R. Feynman '88 |
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