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> Rms Of Discontinuous Sine Wave
pbdavis
Posted: January 23, 2013 05:34 am
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Hi,
How to find the rms value of a discontinuous sine wave of the form shown in the figure.

user posted image
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Sch3mat1c
Posted: January 23, 2013 05:54 am
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The RMS of *any* waveform which is pulsed at some duty cycle D == [0...1] happens to be 1/sqrt(D) times the continuous wave's RMS value.

So a sine wave of, say, 300V peak, has an RMS of 300/sqrt(2) for the sine wave, and if it has a duty cycle of 50%, another 1/sqrt(2), or 150Vrms.

A "pulsed DC" square wave can be thought of as DC with a duty cycle; since the RMS of DC is equal to its value, which is same as the peak value of a "pulsed DC" waveform, the RMS is simply peak/sqrt(D).

Or you can zoom way out and tell your scope to calculate RMS. rolleyes.gif

Tim


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pbdavis
Posted: January 23, 2013 06:01 am
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1/sqrt(2)????
How did you get "2"....D=[0...1]...isn't it?

This post has been edited by pbdavis on January 23, 2013 06:03 am
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Sch3mat1c
Posted: January 25, 2013 04:05 am
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Oops, that should be sqrt(D), or 1/sqrt(2) for D=1/2 blush.gif


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circuitfella11
Posted: May 08, 2013 09:30 am
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QUOTE (pbdavis @ January 23, 2013 01:34 pm)
Hi,
How to find the rms value of a discontinuous sine wave of the form shown in the figure.

user posted image

hi,

from your figure, first get the RMS for your active signal ( those are the waves looking like pulses from far away)

after that, get the duty cycle..

dutycycle=duration of the active signal/period of the function

you multiply both the rms of the active signal and the dutycycle to get the RMS of the figure.


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